How do I pass command line arguments to a Node.js program?

Question

How do I pass command line arguments to a Node.js program?

I have a webserver written in Node.js and I might want to dispatch with a particular folder. I don't know how to get to arguments in JavaScript. I'm running node like this:

$ node server.js folder

here server.js is my server code. Node.js help says this is conceivable:

$ node -h

Usage: node [options] script.js [arguments]

How might I get to those arguments in JavaScript? Some way or another I couldn't discover this data on the web.

arguments javascript nodejs

3 years ago by Bharatv4tg1

3 Answers

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**akshay1995** · Answer 1 · 2021-05-13T12:15:23

To normalize the arguments like a regular javascript function would receive, I do this in my node.js shell scripts:



var args = process.argv.slice(2);

Note that the first arg is usually the path to nodejs, and the second arg is the location of the script you're executing.

**RoliMishra** · Answer 2 · 2021-05-15T13:45:14

We can use the minimist library.

Here is an example of how to use it taken straight from the minimist documentation:

var argv = require('minimist')(process.argv.slice(2));

console.dir(argv);

-

$ node example/parse.js -a beep -b boop

{ _: [], a: 'beep', b: 'boop' }

-

$ node example/parse.js -x 3 -y 4 -n5 -abc --beep=boop foo bar baz

{ _: [ 'foo', 'bar', 'baz' ],

  x: 3,

  y: 4,

  n: 5,

  a: true,

  b: true,

  c: true,

  beep: 'boop' }

**sandhya6gczb** · Answer 3 · 2021-05-17T08:18:33

proccess.argv is an array containing command-line arguments. The first element will be 'node', the second element will be the name of the JavaScript file. The next element will be any additional command-line arguments.



// print process.argv

process.argv.forEach(function (val, index, array) {

  console.log(index + ': ' + val);

});

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How do I pass command line arguments to a Node.js program?

3 Answers

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