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Level 8 Lesson 3 Javascript

It says :
After the function definition, call the doYoga function twice.
function doYoga()
{
console.log("some yoga");
console.log("some more yoga");
console.log("now relax...");
}
doYoga();
doYoga();

I have tried everything, please somebody help me!
by

2 Answers

kshitijrana14
Try this one:

function doYoga()

{
console.log("some yoga");
console.log("some more yoga");
console.log("now relax...");
}
doYoga();
doYoga();

shamin
It isn't working. I have been doing it the same way and it says that the output doesn't match the expected output

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