C++ Program Convert Decimal Number To Binary Number Using Loop

We can convert any decimal number (base-10 (0 to 9)) into binary number (base-2 (0 or 1)) by C++ program.

Decimal Number

Decimal number is a base 10 number because it ranges from 0 to 9, there are total 10 digits between 0 to 9. Any combination of digits is decimal number such as 223, 585, 192, 0, 7 etc.

Binary Number

Binary number is a base 2 number because it is either 0 or 1. Any combination of 0 and 1 is binary number such as 1001, 101, 11111, 101010 etc.

Decimal to Binary Conversion Algorithm In C++ Language

Step 1: Divide the number by 2 through % (modulus operator) and store the remainder in array

Step 2: Divide the number by 2 through / (division operator)

Step 3: Repeat the step 2 until the number is greater than zero

Let's see the C++ example to convert decimal to binary.

#include <iostream>  
using namespace std;  
int main()  
{  
int a[10], n, i;    
cout<<"Enter the number to convert: ";    
cin>>n;    
for(i=0; n>0; i++)    
{    
a[i]=n%2;    
n= n/2;  
}    
cout<<"Binary of the given number= ";    
for(i=i-1 ;i>=0 ;i--)    
{    
cout<<a[i];    
}    
}  

Enter the number to convert: 9
Binary of the given number= 1001

Conclusion

Here, in this tutorial we have learned how to write and implement a C++ Program Convert Decimal Number To Binary Number Using Loop.