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C++ Program to Compute Maximum Sum of the Sub-Array

Hello Everyone!

In this tutorial, we will learn about the most efficient method to compute the maximum sum of the sub-arrays , in the C++ programming language.

To learn about the Array Container in STL, we will recommend you to visit:, where we have discussed it in detail.

The below-given code in CPP programming language explains each of these in detail with the help of comments.


#include <iostream>
#include <bits/stdc++.h>

using namespace std;

int maxSubArray(int m[], int n)

    int sum = 0, s = 0, i;

    for (i = 0; i < n; i++)
        s += m[i];
        if (s < 0)
            s = 0;

        sum = max(s, sum);

    //Sorting the array using the system defined sort() method
    sort(m, m + n);

    //if all the elements are negative then return the largest element of the array
    if (m[n - 1] < 0)
        sum = m[n - 1];

    return sum;

int main()
    cout << "\n\nWelcome to Studytonight :-)\n\n\n";
    cout << " =====  Most Efficient Program to find the Maximum sum of Subarray ===== \n\n";

    int i, n, sum = 0;

    int arr[] = {-2, 1, -3, 4, -1, 2, 1, -5, 4};

    //number of elements in the array
    n = sizeof(arr) / sizeof(arr[0]);

    //Printing the elements of the array
    cout << "\n\n The " << n << " elements of the array are : ";

    for (i = 0; i < n; i++)
        cout << arr[i] << "  ";

    //Calling a method to find the maximum sum of subarray
    sum = maxSubArray(arr, n);

    cout << "\n\n\nThe Maximum sum of the Subarrays of the given array is: " << sum;

    cout << "\n\n\n";

    return 0;


C++ Maximum sum of subarray

We hope that this post helped you develop a better understanding of the logic to compute the maximum sum of the sub-arrays of an array in C++. For any query, feel free to reach out to us via the comments section down below.

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Nikita Pandey is a talented author and expert in programming languages such as C, C++, and Java. Her writing is informative, engaging, and offers practical insights and tips for programmers at all levels.